Why is much less heat generated in long elect | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Joule's law of heating,the heat generated $(H)$ in a conductor is given by $H = I^2Rt$,where $I$ is the current,$R$ is the resistance

Vedclass · Accepted Answer

Cables have low resistance,while filaments have high resistance.

Vedclass · Answer

(C) According to Joule's law of heating,the heat generated $(H)$ in a conductor is given by $H = I^2Rt$,where $I$ is the current,$R$ is the resistance,and $t$ is the time.Electric cables are typically made of thick copper wires,which have a very low resistance $(R)$.In contrast,the filaments of electric bulbs are made of thin tungsten wire,which has a very high resistance $(R)$.Since the heat generated is directly proportional to the resistance $(H \propto R)$,the low resistance of the cables results in significantly less heat generation compared to the high resistance of the bulb filaments.

Why is much less heat generated in long electric cables than in filaments of electric bulbs?

Similar Questions

An electric lamp is marked $100 \, W, 220 \, V$. It is used for $5$ hours daily. Calculate: $(i)$ its resistance while glowing. $(ii)$ energy consumed in $kWh$ per day.

$A$ wire connected to a bulb does not glow,whereas the filament of the bulb glows when the same current is passed through them. Why?

State Joule's law of heating.

The filament of an electric bulb is made of tungsten. Why?

How many electrons constitute a total charge of $1 \ C$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module