With what velocity should an observer move re | vedclass

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(A) The general formula for Doppler's effect is $n' = n \left( \frac{v + v_O}{v - v_S} \right)$,where $n'$ is the observed frequency,$n$ is the source

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Velocity of sound towards the source

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(A) The general formula for Doppler's effect is $n' = n \left( \frac{v + v_O}{v - v_S} \right)$,where $n'$ is the observed frequency,$n$ is the source frequency,$v$ is the speed of sound,$v_O$ is the velocity of the observer,and $v_S$ is the velocity of the source.Given that the source is stationary,$v_S = 0$.We want the observed frequency to be double the source frequency,so $n' = 2n$.Substituting these values into the formula: $2n = n \left( \frac{v + v_O}{v - 0} \right)$.Dividing both sides by $n$: $2 = \frac{v + v_O}{v}$.Multiplying by $v$: $2v = v + v_O$.Solving for $v_O$: $v_O = v$.Since the observer is moving towards the source to hear a higher frequency,the velocity of the observer is equal to the velocity of sound directed towards the source.

With what velocity should an observer move relative to a stationary source so that they hear a sound of double the frequency of the source?

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