Easy
Write the minors and cofactors of the elements of the following determinant: $\left|\begin{array}{rr}2 & -4 \\ 0 & 3\end{array}\right|$
(N/A) The given determinant is $\Delta = \left|\begin{array}{cc}2 & -4 \\ 0 & 3\end{array}\right|$.
The minor of an element $a_{ij}$ is denoted by $M_{ij}$.
For $a_{11} = 2$,$M_{11} = 3$.
For $a_{12} = -4$,$M_{12} = 0$.
For $a_{21} = 0$,$M_{21} = -4$.
For $a_{22} = 3$,$M_{22} = 2$.
The cofactor of an element $a_{ij}$ is denoted by $A_{ij}$ and is given by $A_{ij} = (-1)^{i+j} M_{ij}$.
$A_{11} = (-1)^{1+1} M_{11} = (1)(3) = 3$.
$A_{12} = (-1)^{1+2} M_{12} = (-1)(0) = 0$.
$A_{21} = (-1)^{2+1} M_{21} = (-1)(-4) = 4$.
$A_{22} = (-1)^{2+2} M_{22} = (1)(2) = 2$.
The minor of an element $a_{ij}$ is denoted by $M_{ij}$.
For $a_{11} = 2$,$M_{11} = 3$.
For $a_{12} = -4$,$M_{12} = 0$.
For $a_{21} = 0$,$M_{21} = -4$.
For $a_{22} = 3$,$M_{22} = 2$.
The cofactor of an element $a_{ij}$ is denoted by $A_{ij}$ and is given by $A_{ij} = (-1)^{i+j} M_{ij}$.
$A_{11} = (-1)^{1+1} M_{11} = (1)(3) = 3$.
$A_{12} = (-1)^{1+2} M_{12} = (-1)(0) = 0$.
$A_{21} = (-1)^{2+1} M_{21} = (-1)(-4) = 4$.
$A_{22} = (-1)^{2+2} M_{22} = (1)(2) = 2$.
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