Write the dimensional formula for magnetic flux.
(N/A) Magnetic flux $\Phi_B$ is defined as the product of magnetic field $B$ and the area $A$ perpendicular to it,given by $\Phi_B = B \cdot A$.
From the Lorentz force law,$F = qvB$,we can express the magnetic field as $B = \frac{F}{qv}$.
The dimensional formula for force $F$ is $[M^1 L^1 T^{-2}]$.
The dimensional formula for charge $q$ is $[I^1 T^1]$.
The dimensional formula for velocity $v$ is $[L^1 T^{-1}]$.
Thus,the dimensions of $B$ are $[B] = \frac{[M^1 L^1 T^{-2}]}{[I^1 T^1][L^1 T^{-1}]} = [M^1 T^{-2} I^{-1}]$.
Since magnetic flux $\Phi_B = B \cdot A$,and the area $A$ has dimensions $[L^2]$,we have:
$[\Phi_B] = [M^1 T^{-2} I^{-1}] \cdot [L^2] = [M^1 L^2 T^{-2} I^{-1}]$.
Therefore,the dimensional formula for magnetic flux is $[M^1 L^2 T^{-2} I^{-1}]$.
From the Lorentz force law,$F = qvB$,we can express the magnetic field as $B = \frac{F}{qv}$.
The dimensional formula for force $F$ is $[M^1 L^1 T^{-2}]$.
The dimensional formula for charge $q$ is $[I^1 T^1]$.
The dimensional formula for velocity $v$ is $[L^1 T^{-1}]$.
Thus,the dimensions of $B$ are $[B] = \frac{[M^1 L^1 T^{-2}]}{[I^1 T^1][L^1 T^{-1}]} = [M^1 T^{-2} I^{-1}]$.
Since magnetic flux $\Phi_B = B \cdot A$,and the area $A$ has dimensions $[L^2]$,we have:
$[\Phi_B] = [M^1 T^{-2} I^{-1}] \cdot [L^2] = [M^1 L^2 T^{-2} I^{-1}]$.
Therefore,the dimensional formula for magnetic flux is $[M^1 L^2 T^{-2} I^{-1}]$.
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