Write the formula for the magnetic field due to a current-carrying loop acting as a magnetic dipole at a point on its axis,and compare it with the formula for the electric field of an electric dipole.

(N/A) The magnetic field $B$ on the axis of a circular current loop of radius $R$ at a distance $x$ from its center is given by $B = \frac{\mu_0 I R^2}{2(x^2 + R^2)^{3/2}}$.
For a point far away from the loop $(x \gg R)$,the formula simplifies to $B = \frac{\mu_0}{4\pi} \frac{2m}{x^3}$,where $m = IA$ is the magnetic dipole moment.
The electric field $E$ of an electric dipole at an axial point at distance $x$ (where $x \gg a$) is given by $E = \frac{1}{4\pi \epsilon_0} \frac{2p}{x^3}$,where $p$ is the electric dipole moment.
Comparing the two,we observe that the magnetic field of a magnetic dipole is analogous to the electric field of an electric dipole,with $\frac{\mu_0}{4\pi}$ replacing $\frac{1}{4\pi \epsilon_0}$ and the magnetic dipole moment $m$ replacing the electric dipole moment $p$.