A sample of [Cu(NH_3)_4]SO_4 contains 2.4 tim | vedclass

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(D) The chemical formula $[Cu(NH_3)_4]SO_4$ indicates that $1 \ mol$ of the compound contains $4 \ mol$ of $NH_3$ molecules.First,calculate the total

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(D) The chemical formula $[Cu(NH_3)_4]SO_4$ indicates that $1 \ mol$ of the compound contains $4 \ mol$ of $NH_3$ molecules.First,calculate the total moles of $NH_3$ molecules in the sample:$	ext{Moles of } NH_3 = \frac{2.4 	imes 10^{24}}{6.022 	imes 10^{23}} \approx 4 \ mol$.Since $4 \ mol$ of $NH_3$ are present in $1 \ mol$ of $[Cu(NH_3)_4]SO_4$,the number of moles of the compound is $\frac{4 \ mol}{4} = 1 \ mol$.

$A$ sample of $[Cu(NH_3)_4]SO_4$ contains $2.4 \times 10^{24}$ ammonia molecules. The moles of $[Cu(NH_3)_4]SO_4$ in the given sample will be:

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