CH_3-CH_2-CH(Cl)_2 xrightarrow[{[Excess]}]{{N | vedclass

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(B) The starting material is $1,1$-dichlorobutane,$CH_3-CH_2-CH(Cl)_2$.Treatment with excess $NaNH_2$ (a strong base) causes dehydrohalogenation to fo

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$CH_3-CH_2-C \equiv C-CH_3$

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(B) The starting material is $1,1$-dichlorobutane,$CH_3-CH_2-CH(Cl)_2$.Treatment with excess $NaNH_2$ (a strong base) causes dehydrohalogenation to form an alkyne.$CH_3-CH_2-CH(Cl)_2 \xrightarrow{NaNH_2} CH_3-CH_2-C \equiv CH$ (Compound $P$,$1$-butyne).$1$-butyne has an acidic terminal hydrogen.$CH_3-CH_2-C \equiv CH \xrightarrow{NaNH_2} CH_3-CH_2-C \equiv C^- Na^+$.Reaction with $CH_3Cl$ (an alkyl halide) leads to nucleophilic substitution (alkylation).$CH_3-CH_2-C \equiv C^- + CH_3Cl \rightarrow CH_3-CH_2-C \equiv C-CH_3 + Cl^-$.Thus,$Q$ is $CH_3-CH_2-C \equiv C-CH_3$ ($2$-pentyne).

$CH_3-CH_2-CH(Cl)_2$ $\xrightarrow[{[Excess]}]{{NaNH_2}} P$ $\xrightarrow{{CH_3Cl}} Q$,$Q$ will be

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