The same product $(A)$ is formed in both of the following reactions:
$1. PhMgBr + CH_3-CN \xrightarrow{H_3O^{+}} (A)$
$2. Ph-COOH \xrightarrow{(1) \text{ excess } CH_3Li, (2) H_3O^{+}} (A)$
Identify product $(A)$.

Identify $A$ in the following reaction: $A + CH_3MgBr$ $\xrightarrow{\text{ether}} \text{complex}$ $\xrightarrow{H_3O^{+}} (CH_3)_3C-OH$

Match the following reactions in List-$I$ with their corresponding final products in List-$II$:

List-$I$ (Type of reaction)	List-$II$ (Final Product)
$A$. Reimer-Tiemann reaction	$I$. Chlorobenzene
$B$. Etard reaction	$II$. Salicylaldehyde
$C$. Sandmeyer reaction	$III$. Benzaldehyde
$D$. Friedel-Crafts reaction	$IV$. Acetophenone

The correct answer is:

$HCHO$ (more reactive towards oxidation) + $CH_3CHO \xrightarrow{Conc. NaOH}$ Find out the products of the reaction.

Columns $1$,$2$,and $3$ contain starting materials,reaction conditions,and type of reactions,respectively.

$Column-1$	$Column-2$	$Column-3$
$(I)$ Toluene	$(i)$ $NaOH / Br_2$	$(P)$ Condensation
$(II)$ Acetophenone	$(ii)$ $Br_2 / h\nu$	$(Q)$ Carboxylation
$(III)$ Benzaldehyde	$(iii)$ $(CH_3CO)_2O / CH_3COOK$	$(R)$ Substitution
$(IV)$ Phenol	$(iv)$ $NaOH / CO_2$	$(S)$ Haloform

$(1)$ For the synthesis of benzoic acid,the only $CORRECT$ combination is
$[A] (III) (iv) (R)$ $[B] (IV) (ii) (P)$ $[C] (I) (iv) (Q)$ $[D] (II) (i) (S)$
$(2)$ The only $CORRECT$ combination in which the reaction proceeds through radical mechanism is
$[A] (I) (ii) (R)$ $[B] (II) (iii) (R)$ $[C] (III) (ii) (P)$ $[D] (IV) (i) (Q)$
$(3)$ The only $CORRECT$ combination that gives two different carboxylic acids is
$[A] (IV) (iii) (Q)$ $[B] (III) (iii) (P)$ $[C] (II) (iv) (R)$ $[D] (I) (i) (S)$

The major products $Y$ and $Z$ in the following reactions are