$s-$character in $sp$ hybridised orbitals is
- A$\frac{1}{3}$
- B$\frac{1}{2}$
- C$\frac{1}{4}$
- D$\frac{2}{3}$
Explore More
Similar Questions
The central atom in a molecule is in $sp^2$ hybrid state. The shape of the molecule will be
What is the state of hybridisation of carbon in $(a)$ $CO_3^{2-}$,$(b)$ diamond,and $(c)$ graphite?
Medium
View SolutionWhat is the type of hybridization of the central atom in the following molecules: $BeCl_2, CO_2, BH_3, BCl_3$?
Medium
View SolutionWhich of the following ions has Tetrahedral geometry and $sp^3$ hybridisation for its central atom?
The hybridisation of the central atom in $NF_3$ is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo