CCl_4 has the hybridization: | vedclass

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(D) The central atom in $CCl_4$ is carbon $(C)$.Carbon has $4$ valence electrons.Each chlorine $(Cl)$ atom forms one single bond with carbon,contribut

Vedclass · Accepted Answer

$sp^3$

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(D) The central atom in $CCl_4$ is carbon $(C)$.Carbon has $4$ valence electrons.Each chlorine $(Cl)$ atom forms one single bond with carbon,contributing $4$ electrons for bonding.The total number of electron pairs around the central carbon atom is calculated as: $\frac{1}{2} 	imes (V + M - C + A)$,where $V=4$ (valence electrons of $C$),$M=4$ (monovalent atoms),$C=0$ (cation charge),and $A=0$ (anion charge).Number of electron pairs = $\frac{1}{2} 	imes (4 + 4) = 4$.Since there are $4$ bond pairs and $0$ lone pairs,the hybridization is $sp^3$,which corresponds to a tetrahedral geometry.

$CCl_4$ has the hybridization:

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