Be in BeCl_2 undergoes | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The atomic number of $Be$ is $4$. The ground state electronic configuration is $1s^2, 2s^2$.In the excited state,one electron from the $2s$ orbita

Vedclass · Accepted Answer

Diagonal hybridization

Vedclass · Answer

(A) The atomic number of $Be$ is $4$. The ground state electronic configuration is $1s^2, 2s^2$.In the excited state,one electron from the $2s$ orbital is promoted to the $2p$ orbital,resulting in the configuration $1s^2, 2s^1, 2p^1$.These two orbitals ($2s$ and $2p$) hybridize to form two equivalent $sp$ hybrid orbitals.This type of hybridization is known as diagonal or linear hybridization,which results in a linear geometry for the $BeCl_2$ molecule.

$Be$ in $BeCl_2$ undergoes

Similar Questions

The nature of hybridization in the $NH_3$ molecule is

Which pair of molecules has different hybridisation but the same shape?

What is the hybridisation of carbon $C_2$ and $C_4$ respectively in the molecule $CH_3-CH=CH-CH_3$?

As the $s$-character of the hybrid orbital decreases,the bond angle ...........

The hybridizations of carbon in graphite,diamond and $C_{60}$ are respectively

Vedclass Test Series

Exam Paper Generator

Online Exam Module