Which of the following molecules is linear?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the shape of the molecules,we look at their hybridization and $VSEPR$ theory: $1$. $BeCl_2$: Beryllium has $2$ valence electrons. It

Vedclass · Accepted Answer

$BeCl_2$

Vedclass · Answer

(A) To determine the shape of the molecules,we look at their hybridization and $VSEPR$ theory: $1$. $BeCl_2$: Beryllium has $2$ valence electrons. It forms two bonds with Chlorine atoms. The hybridization is $sp$,resulting in a linear geometry with a bond angle of $180^{\circ}$. $2$. $H_2O$: Oxygen has $6$ valence electrons. It forms two bonds with Hydrogen and has two lone pairs. The hybridization is $sp^3$,resulting in a bent or $V$-shape. $3$. $SO_2$: Sulfur has $6$ valence electrons. It forms two double bonds with Oxygen and has one lone pair. The hybridization is $sp^2$,resulting in a bent shape. $4$. $CH_4$: Carbon has $4$ valence electrons. It forms four bonds with Hydrogen. The hybridization is $sp^3$,resulting in a tetrahedral geometry. Therefore,$BeCl_2$ is the linear molecule.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $XeF_4$	$I$. Square pyramidal
$B$. $ClF_3$	$II$. Pentagonal bipyramidal
$C$. $BrF_5$	$III$. Square planar
$D$. $IF_7$	$IV$. Bent $T$-shape

Similar Questions

In which of the following is the bond angle maximum?

Identify the incorrect statement for $PCl_5$ from the following.

Match the following:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $XeF_4$ $I$. Square pyramidal

$B$. $ClF_3$ $II$. Pentagonal bipyramidal

$C$. $BrF_5$ $III$. Square planar

$D$. $IF_7$ $IV$. Bent $T$-shape

The correct order of $H-N-H$ bond angles of ammonia,ammonium ion,and amide ion is:

In the ozone $(O_3)$ molecule,the formal charge on the central oxygen atom is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module