In the reaction CH_2 = CH_2 xrightarrow[text{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The reaction of ethene $(CH_2=CH_2)$ with hypochlorous acid $(HOCl)$ follows electrophilic addition to form $2$-chloroethanol $(M = CH_2Cl-CH

Vedclass · Accepted Answer

$CH_2Cl-CH_2OH$ and $NaOH(aq)$

Vedclass · Answer

(A) $1$. The reaction of ethene $(CH_2=CH_2)$ with hypochlorous acid $(HOCl)$ follows electrophilic addition to form $2$-chloroethanol $(M = CH_2Cl-CH_2OH)$.$2$. $2$-chloroethanol $(CH_2Cl-CH_2OH)$ reacts with aqueous sodium hydroxide $(NaOH)$ via an intramolecular nucleophilic substitution reaction (or hydrolysis) to form ethylene glycol $(CH_2OH-CH_2OH)$.$3$. Therefore,$M$ is $CH_2Cl-CH_2OH$ and $R$ is $NaOH(aq)$.

In the reaction $CH_2 = CH_2$ $\xrightarrow[\text{acid}]{\text{Hypochlorous}} M$ $\xrightarrow{R} \begin{array}{c} CH_2OH \\ | \\ CH_2OH \end{array}$,$M$ and $R$ are respectively:

Similar Questions

Which compound on reductive ozonolysis produces at least one mole of $CO_2$?

$Me-C \equiv C-CH_2-COCl \xrightarrow{H_2/Pd-C} ?$

Aqueous solution of sodium salt of $2-$methylbutanedioic acid on Kolbe's electrolysis gives:

Butane can be prepared from butene by reaction with........

The reaction of propene with $HOCl$ proceeds via the addition of which of the following in the first step?

Vedclass Test Series

Exam Paper Generator

Online Exam Module