An organic compound A reacts with methyl magn | vedclass

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(C) $1$. The reaction of an aldehyde or ketone with $CH_3MgI$ followed by hydrolysis yields an alcohol.$2$. Compound $B$ gives a blue color in the Vic

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Acetaldehyde,isopropyl alcohol

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(C) $1$. The reaction of an aldehyde or ketone with $CH_3MgI$ followed by hydrolysis yields an alcohol.$2$. Compound $B$ gives a blue color in the Victor Meyer test,which indicates that $B$ is a secondary $(2^{\circ})$ alcohol.$3$. Acetaldehyde $(CH_3CHO)$ reacts with $CH_3MgI$ to form an addition product,which on hydrolysis gives isopropyl alcohol $(CH_3CH(OH)CH_3)$.$4$. Isopropyl alcohol is a secondary alcohol,which gives a blue color in the Victor Meyer test.$5$. Therefore,$A$ is acetaldehyde and $B$ is isopropyl alcohol.

An organic compound $A$ reacts with methyl magnesium iodide to form an addition product,which on hydrolysis gives compound $B$. Compound $B$ gives a blue color in the Victor Meyer test. What are compounds $A$ and $B$ respectively?

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