For the combustion reaction C_2H_{6(g)} + nO_ | vedclass

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Question

(B) The combustion reaction is $C_2H_6 + O_2 	o CO_2 + H_2O$. To balance the carbon atoms,we place a coefficient of $2$ before $CO_2$: $C_2H_6 + O_2

Vedclass · Accepted Answer

$2:3$

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(B) The combustion reaction is $C_2H_6 + O_2 	o CO_2 + H_2O$. To balance the carbon atoms,we place a coefficient of $2$ before $CO_2$: $C_2H_6 + O_2 	o 2CO_2 + H_2O$. To balance the hydrogen atoms,we place a coefficient of $3$ before $H_2O$: $C_2H_6 + O_2 	o 2CO_2 + 3H_2O$. Finally,balancing oxygen atoms gives $C_2H_6 + \frac{7}{2}O_2 	o 2CO_2 + 3H_2O$,or multiplying by $2$ to get whole numbers: $2C_2H_6 + 7O_2 	o 4CO_2 + 6H_2O$. The coefficients of $CO_2$ and $H_2O$ are $4$ and $6$ respectively. The ratio is $4:6$,which simplifies to $2:3$.

For the combustion reaction $C_2H_{6(g)} + nO_{2(g)} \to CO_{2(g)} + H_2O_{(l)}$,what is the ratio of the stoichiometric coefficients of $CO_2$ and $H_2O$ in the balanced equation?

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