Al^{3+} has a lower ionic radius than Mg^{2+} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $Al^{3+}$ and $Mg^{2+}$ have an equal number of electrons ($10$ electrons) and are,therefore,isoelectronic.For isoelectronic species,the ionic rad

Vedclass · Accepted Answer

$Al^{3+}$ has a higher nuclear charge than $Mg^{2+}$

Vedclass · Answer

(B) $Al^{3+}$ and $Mg^{2+}$ have an equal number of electrons ($10$ electrons) and are,therefore,isoelectronic.For isoelectronic species,the ionic radius depends upon the effective nuclear charge $(Z_{eff})$.Ionic radius is inversely proportional to the effective nuclear charge.Since $Al$ $(Z=13)$ has a higher atomic number than $Mg$ $(Z=12)$,$Al^{3+}$ experiences a greater effective nuclear charge than $Mg^{2+}$.Consequently,the electrons in $Al^{3+}$ are pulled more strongly towards the nucleus,resulting in a smaller ionic radius.

$Al^{3+}$ has a lower ionic radius than $Mg^{2+}$ because

Similar Questions

The increasing order of atomic radii of the following Group $13$ elements is:

The correct order of the ionic radii of $O^{2-}, N^{3-}, F^{-}, Mg^{2+}, Na^{+}$ and $Al^{3+}$ is

Which one of the following indicates the correct order of atomic size of the given elements?

On moving down a group of representative elements,both atomic and ionic radii increase with an increase in:

Which statement is correct regarding the atomic and ionic radii of potassium $(K)$ and bromine $(Br)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module