What is acceleration? What is its direction,and state its $SI$ unit.
(N/A) Acceleration is defined as the rate of change of velocity with respect to time.
Its direction is the same as the direction of the change in velocity.
The $SI$ unit of acceleration is $m/s^2$ or $m s^{-2}$.
Its direction is the same as the direction of the change in velocity.
The $SI$ unit of acceleration is $m/s^2$ or $m s^{-2}$.
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Match the items in Column-$I$ with the items in Column-$II$ correctly.
Column-$I$ Column-$II$ $(1)$ Acceleration is positive $(a)$ Speed of the particle decreases $(2)$ Acceleration is negative $(b)$ Speed of the particle increases $(c)$ Speed of the particle keeps changing
| Column-$I$ | Column-$II$ |
|---|---|
| $(1)$ Acceleration is positive | $(a)$ Speed of the particle decreases |
| $(2)$ Acceleration is negative | $(b)$ Speed of the particle increases |
| $(c)$ Speed of the particle keeps changing |
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View SolutionMatch the following columns.
Column $I$ Column $II$ $(A)$ $\frac{dv}{dt}$ $(p)$ Acceleration $(B)$ $\frac{d|v|}{dt}$ $(q)$ Magnitude of acceleration $(C)$ $\frac{dr}{dt}$ $(r)$ Velocity $(D)$ $\left|\frac{dr}{dt}\right|$ $(s)$ Magnitude of velocity
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| $(A)$ $\frac{dv}{dt}$ | $(p)$ Acceleration |
| $(B)$ $\frac{d|v|}{dt}$ | $(q)$ Magnitude of acceleration |
| $(C)$ $\frac{dr}{dt}$ | $(r)$ Velocity |
| $(D)$ $\left|\frac{dr}{dt}\right|$ | $(s)$ Magnitude of velocity |
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View SolutionThe velocity of a particle is given as $\vec{v} = -x\hat{i} + 2y\hat{j} - z\hat{k} \text{ m/s}$. The magnitude of acceleration at point $(1, 2, 4)$ is . . . . . . $\text{m/s}^2$.
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View SolutionThe distance travelled by a body moving along a line in time $t$ is proportional to $t^3$. The acceleration-time $(a, t)$ graph for the motion of the body will be
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