The equivalent mass of an element X is 9. If | vedclass

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(C) Molecular mass $= 2 	imes 	ext{Vapor density} = 2 	imes 66.75 = 133.50$. The formula of the chloride salt is $XCl_n$,where $n$ is the valency.

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) Molecular mass $= 2 	imes 	ext{Vapor density} = 2 	imes 66.75 = 133.50$. The formula of the chloride salt is $XCl_n$,where $n$ is the valency. Molecular mass $= 	ext{Atomic mass of } X + n 	imes 	ext{Atomic mass of } Cl$. Atomic mass of $X = 	ext{Equivalent mass} 	imes 	ext{Valency} = 9 	imes n$. Substituting the values: $133.50 = 9n + n 	imes 35.5$. $133.50 = 44.5n$. $n = \frac{133.50}{44.5} = 3$. Therefore,the valency of element $X$ is $3$.

Isotope	$\%$ Natural Abundance	Molar Mass $(g/mol)$
$^{35}Cl$	$75.77$	$34.9689$
$^{37}Cl$	$24.23$	$36.9659$

The equivalent mass of an element $X$ is $9$. If the vapor density of its chloride salt is $66.75$,determine the valency of element $X$.

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