Why are transition elements less electropositive than the metals of group-$1$ and group-$2$?
- AThey have higher ionization enthalpy.
- BThey have lower ionization enthalpy.
- CThey have smaller atomic radii.
- DThey have larger atomic radii.
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Similar Questions
Match the elements in List-$I$ with their electronic configurations in List-$II$.
List-$I$ List-$II$ $(1)$ $Ti^+$ $(A)$ $(n-1)d^4ns^2$ $(2)$ $_{30}Zn$ $(B)$ $(n-1)d^{10}ns^1$ $(3)$ $_{24}Cr$ $(C)$ $(n-1)d^2ns^0$ $(4)$ $_{29}Cu$ $(D)$ $(n-1)d^5ns^1$ $(E)$ $(n-1)d^0ns^2$ $(F)$ $(n-1)d^{10}ns^2$
| List-$I$ | List-$II$ |
| $(1)$ $Ti^+$ | $(A)$ $(n-1)d^4ns^2$ |
| $(2)$ $_{30}Zn$ | $(B)$ $(n-1)d^{10}ns^1$ |
| $(3)$ $_{24}Cr$ | $(C)$ $(n-1)d^2ns^0$ |
| $(4)$ $_{29}Cu$ | $(D)$ $(n-1)d^5ns^1$ |
| $(E)$ $(n-1)d^0ns^2$ | |
| $(F)$ $(n-1)d^{10}ns^2$ |
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View SolutionThe correct order of decreasing second ionisation enthalpy of $Ti(22), V(23), Cr(24)$ and $Mn(25)$ is
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