$60 \ g$ of a compound on analysis gave $C = 24 \ g$,$H = 4 \ g$ and $O = 32 \ g$. Its empirical formula is

  • A
    $C_2H_4O_2$
  • B
    $C_2H_2O$
  • C
    $CH_2O_2$
  • D
    $CH_2O$

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