A, B and C can complete a piece of work in 15 | vedclass

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(B) $1$. Calculate the efficiency of each person:Efficiency of $A = 120 / 15 = 8$ units/day.Efficiency of $B = 120 / 30 = 4$ units/day.Efficiency of $

Vedclass · Accepted Answer

$10\frac{2}{15}$

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(B) $1$. Calculate the efficiency of each person:Efficiency of $A = 120 / 15 = 8$ units/day.Efficiency of $B = 120 / 30 = 4$ units/day.Efficiency of $C = 120 / 40 = 3$ units/day.$2$. Assume $A$ and $B$ did not leave the work. Add the work they would have done if they had stayed until the end:Work done by $A$ in $2$ days $= 2 	imes 8 = 16$ units.Work done by $B$ in $4$ days $= 4 	imes 4 = 16$ units.$3$. Calculate the new total work:Total work $= 120 + 16 + 16 = 152$ units.$4$. Calculate the total time taken by $A, B$ and $C$ working together:Combined efficiency $= 8 + 4 + 3 = 15$ units/day.Total time $= 152 / 15 = 10\frac{2}{15}$ days.

$A, B$ and $C$ can complete a piece of work in $15, 30$ and $40$ days respectively. They started the work together,but $A$ left $2$ days before the completion of the work and $B$ left $4$ days before the completion of the work. In how many days was the work completed?

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