(15 times 0.40)^{4} div (1080 div 30)^{4} tim | vedclass

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(B) Given equation: $(15 	imes 0.40)^{4} \div (1080 \div 30)^{4} 	imes (27 	imes 8)^{4} = (3 	imes 2)^{?+5}$Step $1$: Simplify the terms inside th

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(B) Given equation: $(15 	imes 0.40)^{4} \div (1080 \div 30)^{4} 	imes (27 	imes 8)^{4} = (3 	imes 2)^{?+5}$Step $1$: Simplify the terms inside the parentheses.$(15 	imes 0.40) = 6$$(1080 \div 30) = 36$$(27 	imes 8) = 216$Step $2$: Substitute these values into the equation.$(6)^{4} \div (36)^{4} 	imes (216)^{4} = (6)^{?+5}$Step $3$: Express all bases as powers of $6$.$36 = 6^{2}$ and $216 = 6^{3}$So,$(6)^{4} \div (6^{2})^{4} 	imes (6^{3})^{4} = (6)^{?+5}$$(6)^{4} \div (6)^{8} 	imes (6)^{12} = (6)^{?+5}$Step $4$: Use exponent laws $a^{m} \div a^{n} = a^{m-n}$ and $a^{m} 	imes a^{n} = a^{m+n}$.$(6)^{4-8+12} = (6)^{?+5}$$(6)^{8} = (6)^{?+5}$Step $5$: Equate the exponents.$8 = ? + 5$$? = 8 - 5 = 3$

$(15 \times 0.40)^{4} \div (1080 \div 30)^{4} \times (27 \times 8)^{4} = (3 \times 2)^{?+5}$

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