5 mL of N HCl,20 mL of N/2 H_2SO_4,and 30 | vedclass

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(D) The formula for the normality of a mixture is $N_{mix}V_{mix} = N_1V_1 + N_2V_2 + N_3V_3$. Given: $N_1 = 1 \ N, V_1 = 5 \ mL$ $N_2 = 1/2 \ N, V_2

Vedclass · Accepted Answer

$N/40$

Vedclass · Answer

(D) The formula for the normality of a mixture is $N_{mix}V_{mix} = N_1V_1 + N_2V_2 + N_3V_3$. Given: $N_1 = 1 \ N, V_1 = 5 \ mL$ $N_2 = 1/2 \ N, V_2 = 20 \ mL$ $N_3 = 1/3 \ N, V_3 = 30 \ mL$ $V_{mix} = 1 \ L = 1000 \ mL$ Substituting the values: $N_{mix} 	imes 1000 = (1 	imes 5) + (1/2 	imes 20) + (1/3 	imes 30)$ $N_{mix} 	imes 1000 = 5 + 10 + 10$ $N_{mix} 	imes 1000 = 25$ $N_{mix} = 25 / 1000 = 1 / 40 \ N$ Thus,the normality is $N/40$.

$5 \ mL$ of $N \ HCl$,$20 \ mL$ of $N/2 \ H_2SO_4$,and $30 \ mL$ of $N/3 \ HNO_3$ are mixed together and the volume is made up to $1 \ L$. The normality of the resulting solution is:

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