sin 2A = 2 sin A is true when A = (in ^{circ} | vedclass

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(D) We are given the equation $\sin 2A = 2 \sin A$.Using the trigonometric identity $\sin 2A = 2 \sin A \cos A$,we can rewrite the equation as:$2 \sin

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$0$

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(D) We are given the equation $\sin 2A = 2 \sin A$.Using the trigonometric identity $\sin 2A = 2 \sin A \cos A$,we can rewrite the equation as:$2 \sin A \cos A = 2 \sin A$$2 \sin A \cos A - 2 \sin A = 0$$2 \sin A (\cos A - 1) = 0$This implies either $\sin A = 0$ or $\cos A = 1$.For $\sin A = 0$,$A = 0^{\circ}, 180^{\circ}, \dots$For $\cos A = 1$,$A = 0^{\circ}, 360^{\circ}, \dots$Checking the given options,for $A = 0^{\circ}$:$LHS$: $\sin 2(0^{\circ}) = \sin 0^{\circ} = 0$$RHS$: $2 \sin 0^{\circ} = 2(0) = 0$Since $LHS$ = $RHS$,the correct option is $D$.

$\sin 2A = 2 \sin A$ is true when $A =$ (in $^{\circ}$)

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$\sin 2A = 2 \sin A$ is true when $A =$ (in $^{\circ}$)

Similar Questions

Evaluate:$\operatorname{cosec} 31^{\circ}-\sec 59^{\circ}$

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