frac{1+tan ^{2} A}{1+cot ^{2} A} = dots | vedclass

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(D) We know the trigonometric identities: $1 + 	an^2 A = \sec^2 A$ and $1 + \cot^2 A = \csc^2 A$.Substituting these into the expression:$\frac{1+	an

Vedclass · Accepted Answer

$	an ^{2} A$

Vedclass · Answer

(D) We know the trigonometric identities: $1 + 	an^2 A = \sec^2 A$ and $1 + \cot^2 A = \csc^2 A$.Substituting these into the expression:$\frac{1+	an ^{2} A}{1+\cot ^{2} A} = \frac{\sec^2 A}{\csc^2 A}$Since $\sec A = \frac{1}{\cos A}$ and $\csc A = \frac{1}{\sin A}$,we have:$= \frac{\frac{1}{\cos^2 A}}{\frac{1}{\sin^2 A}} = \frac{\sin^2 A}{\cos^2 A} = 	an^2 A$.

$\frac{1+\tan ^{2} A}{1+\cot ^{2} A} = \dots$

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