sqrt{8+4 sqrt{3}} = ldots | vedclass

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(C) To simplify the expression $\sqrt{8+4 \sqrt{3}}$,we can rewrite it in the form $\sqrt{a+b+2\sqrt{ab}} = \sqrt{a} + \sqrt{b}$.First,rewrite the exp

Vedclass · Accepted Answer

$\sqrt{6}+\sqrt{2}$

Vedclass · Answer

(C) To simplify the expression $\sqrt{8+4 \sqrt{3}}$,we can rewrite it in the form $\sqrt{a+b+2\sqrt{ab}} = \sqrt{a} + \sqrt{b}$.First,rewrite the expression as $\sqrt{8 + 2 \cdot 2 \sqrt{3}} = \sqrt{8 + 2 \sqrt{4 \cdot 3}} = \sqrt{8 + 2 \sqrt{12}}$.We need two numbers whose sum is $8$ and whose product is $12$.These numbers are $6$ and $2$,since $6+2=8$ and $6 	imes 2=12$.Therefore,$\sqrt{8 + 2 \sqrt{12}} = \sqrt{6} + \sqrt{2}$.

$\sqrt{8+4 \sqrt{3}} = \ldots$

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