Delta ABC sim Delta PQR for the correspondenc | vedclass

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(D) Given that $\Delta ABC \sim \Delta PQR$.For similar triangles,the ratio of their perimeters is equal to the ratio of their corresponding sides.The

Vedclass · Accepted Answer

$35$

Vedclass · Answer

(D) Given that $\Delta ABC \sim \Delta PQR$.For similar triangles,the ratio of their perimeters is equal to the ratio of their corresponding sides.Therefore,$\frac{	ext{Perimeter of } \Delta ABC}{	ext{Perimeter of } \Delta PQR} = \frac{AB}{PQ}$.Given $AB = 8$,$PQ = 14$,and the perimeter of $\Delta ABC = 20$.Let the perimeter of $\Delta PQR$ be $x$.Substituting the values: $\frac{20}{x} = \frac{8}{14}$.Simplifying the fraction: $\frac{20}{x} = \frac{4}{7}$.Cross-multiplying: $4x = 20 	imes 7$.$4x = 140$.$x = \frac{140}{4} = 35$.Thus,the perimeter of $\Delta PQR$ is $35$.

$\Delta ABC \sim \Delta PQR$ for the correspondence $ABC \leftrightarrow PQR$. If $AB = 8$,$PQ = 14$ and the perimeter of $\Delta ABC$ is $20$,find the perimeter of $\Delta PQR$.

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