If A(x_{1}, y_{1}) and B(x_{2}, y_{2}) are th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The distance between two points $A(x_{1}, y_{1})$ and $B(x_{2}, y_{2})$ in a Cartesian plane is given by the distance formula.According to the dis

Vedclass · Accepted Answer

$\sqrt{(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}$

Vedclass · Answer

(A) The distance between two points $A(x_{1}, y_{1})$ and $B(x_{2}, y_{2})$ in a Cartesian plane is given by the distance formula.According to the distance formula,the distance $d$ between points $A$ and $B$ is calculated as $d(A, B) = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$.Since $(x_{2}-x_{1})^{2} = (x_{1}-x_{2})^{2}$ and $(y_{2}-y_{1})^{2} = (y_{1}-y_{2})^{2}$,the formula can also be written as $d(A, B) = \sqrt{(x_{1}-x_{2})^{2} + (y_{1}-y_{2})^{2}}$.Therefore,option $A$ is the correct answer.

If $A(x_{1}, y_{1})$ and $B(x_{2}, y_{2})$ are the given points,then $d(A, B) = $ .........

Similar Questions

If $G$ is the centroid of a triangle having vertices $A(3h, 3k)$,$B(-3a, 0)$,and $C(3a, 0)$,then prove that $AB^2 + BC^2 + AC^2 = 3(GA^2 + GB^2 + GC^2)$.

The distance between the points $(0, 5)$ and $(-5, 0)$ is

In which ratio does the $X$-axis divide the line segment joining $A(1, 2)$ and $B(4, -5)$ starting from $A$?

The point on the $Y-$ axis which is equidistant from $P(3,2)$ and $Q(-1,-5)$ is $\ldots \ldots \ldots \ldots$

Show that $A(1, 4)$,$B(7, -2)$,and $C(9, 6)$ are the vertices of an isosceles triangle.

Vedclass Test Series

Exam Paper Generator

Online Exam Module