(B) To solve $(\sqrt{3}+2)^{2}$,we use the algebraic identity $(a+b)^{2} = a^{2} + 2ab + b^{2}$.Here,$a = \sqrt{3}$ and $b = 2$.Substituting these val

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(B) To solve $(\sqrt{3}+2)^{2}$,we use the algebraic identity $(a+b)^{2} = a^{2} + 2ab + b^{2}$.Here,$a = \sqrt{3}$ and $b = 2$.Substituting these values into the identity:$(\sqrt{3}+2)^{2} = (\sqrt{3})^{2} + 2(\sqrt{3})(2) + (2)^{2}$$= 3 + 4\sqrt{3} + 4$$= 7 + 4\sqrt{3}$.