3+6+9+12+ldots+300 = ldots | vedclass

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(B) The given series is $3+6+9+\ldots+300$.We can factor out $3$ from the series:$3(1+2+3+\ldots+100)$.The sum of the first $n$ natural numbers is giv

Vedclass · Accepted Answer

$15,150$

Vedclass · Answer

(B) The given series is $3+6+9+\ldots+300$.We can factor out $3$ from the series:$3(1+2+3+\ldots+100)$.The sum of the first $n$ natural numbers is given by the formula $S_n = \frac{n(n+1)}{2}$.Here,$n = 100$,so the sum of the series $1+2+3+\ldots+100$ is $\frac{100(100+1)}{2} = \frac{100 	imes 101}{2} = 50 	imes 101 = 5050$.Multiplying this by $3$,we get $3 	imes 5050 = 15,150$.

$3+6+9+12+\ldots+300 = \ldots$

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