A xrightarrow[begin{smallmatrix} (ii) CN^{-} | vedclass

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(C) The reaction sequence is as follows:$1$. $4-$Bromotoluene reacts with $Cl_{2}$ in the presence of heat (free radical substitution) to form $4-$bro

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$4-$Bromotoluene

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(C) The reaction sequence is as follows:$1$. $4-$Bromotoluene reacts with $Cl_{2}$ in the presence of heat (free radical substitution) to form $4-$bromobenzyl chloride $(Br-C_{6}H_{4}-CH_{2}Cl)$.$2$. This product then reacts with $CN^{-}$ (nucleophilic substitution) to form $4-$bromophenylacetonitrile $(Br-C_{6}H_{4}-CH_{2}CN)$.$3$. Finally,acid-catalyzed hydrolysis of the nitrile group yields $4-$bromophenylacetic acid $(Br-C_{6}H_{4}-CH_{2}COOH)$.Therefore,the starting material '$A$' is $4-$bromotoluene.

$A \xrightarrow[\begin{smallmatrix} (ii) CN^{-} \\ (iii) H_{2}O/H^{+} \end{smallmatrix}]{(1) Cl_{2}, \Delta }$ $4-$Bromophenyl acetic acid.
In the above reaction '$A$' is ....

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$A \xrightarrow[\begin{smallmatrix} (ii) CN^{-} \\ (iii) H_{2}O/H^{+} \end{smallmatrix}]{(1) Cl_{2}, \Delta }$ $4-$Bromophenyl acetic acid.In the above reaction '$A$' is ....