A xrightarrow[text{(ii) } H_3O^{+}]{text{(i) | vedclass

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(A) $1$. Molar mass of $A$ is $121 \ g/mol$. Benzamide $(C_6H_5CONH_2)$ has a molar mass of $121 \ g/mol$ and contains nitrogen,thus giving a positive

Vedclass · Accepted Answer

$A$ = Benzamide,$B$ = Benzoic acid,$C$ = Ethyl benzoate

Vedclass · Answer

(A) $1$. Molar mass of $A$ is $121 \ g/mol$. Benzamide $(C_6H_5CONH_2)$ has a molar mass of $121 \ g/mol$ and contains nitrogen,thus giving a positive Lassaigne's test.$2$. The reaction of benzamide with $NaOH$ followed by $H_3O^+$ is an alkaline hydrolysis,which converts the amide group $(-CONH_2)$ into a carboxylic acid group $(-COOH)$,yielding benzoic acid $(B)$.$3$. Benzoic acid $(B)$ reacts with $NaHCO_3$ to release $CO_2$ gas,causing effervescence.$4$. The reaction of benzoic acid $(B)$ with ethanol $(EtOH)$ in the presence of $H_2SO_4$ and heat is an esterification reaction,which produces ethyl benzoate $(C)$,characterized by a fruity smell.

Column-$I$	Column-$II$
$(A)$ $CF_3COOH$	$(i)$ $3.41$
$(B)$ Benzoic acid	$(ii)$ $4.76$
$(C)$ $CH_3COOH$	$(iii)$ $0.23$
$(D)$ $4$-nitrobenzoic acid	$(iv)$ $4.20$

Similar Questions

An ester $(A)$ with molecular formula $C_9H_{10}O_2$ is reacted with an excess of $CH_3MgBr$. The resulting product is treated with concentrated $H_2SO_4$ to form an olefin $(B)$. Ozonolysis of $(B)$ yields a ketone with the formula $C_8H_8O$. What is the structure of $(A)$?

Match Column-$I$ with Column-$II$ based on the $pK_a$ values of the given carboxylic acids:
Column-$I$ Column-$II$
$(A)$ $CF_3COOH$ $(i)$ $3.41$
$(B)$ Benzoic acid $(ii)$ $4.76$
$(C)$ $CH_3COOH$ $(iii)$ $0.23$
$(D)$ $4$-nitrobenzoic acid $(iv)$ $4.20$

The final product $(III)$ obtained in the reaction sequence is:
$CH_3-CH_2-COOH$ $\xrightarrow{PCl_3} I$ $\xrightarrow{C_6H_6/AlCl_3} II$ $\xrightarrow{NH_2-NH_2/\text{base/heat}} III$

Assertion : The $pK_a$ of acetic acid is lower than that of phenol.
Reason : Phenoxide ion is more resonance stabilised.

What are the products formed at the anode during Kolbe synthesis?

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