An ester $(A)$ with molecular formula $C_9H_{10}O_2$ is reacted with an excess of $CH_3MgBr$. The resulting product is treated with concentrated $H_2SO_4$ to form an olefin $(B)$. Ozonolysis of $(B)$ yields a ketone with the formula $C_8H_8O$. What is the structure of $(A)$?
- A$C_6H_5COOC_2H_5$
- B$CH_3OCH_2COC_6H_5$
- C$CH_3COC_6H_4COCH_3$
- D$C_6H_5COOC_6H_5$
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Similar Questions
The major products $Q$ and $R$ from the following reactions,respectively are:
DifficultTS EAMCET 2021
View SolutionWhat are $X, Y, Z$ in the following reaction sequence?
$CH_3-CH=CH-CH_3$ $\xrightarrow{X} CH_3COOH$ $\xrightarrow{Y} CH_3COCl$ $\xrightarrow[\text{Anhy. } AlCl_3]{\text{Benzene}} Z$
$CH_3-CH=CH-CH_3$ $\xrightarrow{X} CH_3COOH$ $\xrightarrow{Y} CH_3COCl$ $\xrightarrow[\text{Anhy. } AlCl_3]{\text{Benzene}} Z$
In the following reaction,$X$ and $Y$ are respectively
$CH_3 COOH + NH_3$ $\longrightarrow X \stackrel{\Delta}{}$ ${\longrightarrow} Y + H_2 O$
$CH_3 COOH + NH_3$ $\longrightarrow X \stackrel{\Delta}{}$ ${\longrightarrow} Y + H_2 O$
Which of the following reactions produce carboxylic acids?
$(a)$ $MnO_2$ with $CH_3COCH_3$
$(b)$ $Ph-CCl_3 \xrightarrow[(ii) H_2O/H^+]{(i) aq. NaOH} PhCOOH$
$(c)$ $C_2H_5Br \xrightarrow[(iii) H_2O/H^+]{(i) Mg, (ii) CO_2} C_2H_5COOH$
$(d)$ $CH_3CH=CHCH_3 \xrightarrow[\Delta]{K_2Cr_2O_7/H_2SO_4} 2CH_3COOH$
$(a)$ $MnO_2$ with $CH_3COCH_3$
$(b)$ $Ph-CCl_3 \xrightarrow[(ii) H_2O/H^+]{(i) aq. NaOH} PhCOOH$
$(c)$ $C_2H_5Br \xrightarrow[(iii) H_2O/H^+]{(i) Mg, (ii) CO_2} C_2H_5COOH$
$(d)$ $CH_3CH=CHCH_3 \xrightarrow[\Delta]{K_2Cr_2O_7/H_2SO_4} 2CH_3COOH$
Assertion : The $pK_a$ of acetic acid is lower than that of phenol.
Reason : Phenoxide ion is more resonance stabilised.
Reason : Phenoxide ion is more resonance stabilised.
MediumAIIMS 2004
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