$\int e^x \left[ \frac{2 + \sin 2x}{1 + \cos 2x} \right] dx =$

  • A
    $e^x \tan x + C$
  • B
    $e^x + \tan x + C$
  • C
    $2e^x \tan x + C$
  • D
    $e^x \tan 2x + C$

Explore More

Similar Questions

$\int e^{x}\left(\frac{1-x}{1+x^{2}}\right)^{2} \,d x=$

The value of $ \int \frac{e^{x}\left(x^{2} \tan ^{-1} x+\tan ^{-1} x+1\right)}{x^{2}+1} d x $ is equal to

If $\int e^{2x} \frac{2(\sin 2x \cos 2x - 1)}{2 \sin^2 2x} dx = A e^{2x} \cot 2x + c$ (where $c$ is the constant of integration), then $A^3 =$ ?

$\int {{e^x}\left[ {f(x) + f'(x)} \right]\,dx} $ is equal to

$\int {{e^{2x}}( - \sin x + 2\cos x)\,dx} = $

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo