$A$ bag contains $4$ red and $3$ black balls. One ball is drawn and then replaced in the bag and the process is repeated. Let $X$ denote the number of times a black ball is drawn in $3$ draws. Assuming that at each draw each ball is equally likely to be selected,the probability distribution of $X$ is given by:

  • A
    $X$$0$$1$$2$$3$
    $P(X)$$(\frac{4}{7})^3$$\frac{9}{7} \times (\frac{4}{7})^2$$\frac{12}{7} \times (\frac{3}{7})^2$$(\frac{3}{7})^3$
  • B
    $X$$0$$1$$2$$3$
    $P(X)$$(\frac{3}{7})^3$$\frac{12}{7} \times (\frac{3}{7})^2$$\frac{9}{7} \times (\frac{4}{7})^2$$(\frac{4}{7})^3$
  • C
    $X$$0$$1$$2$$3$
    $P(X)$$(\frac{3}{7})^3$$\frac{9}{7} \times (\frac{4}{7})^2$$\frac{12}{7} \times (\frac{3}{7})^2$$(\frac{4}{7})^3$
  • D
    $X$$0$$1$$2$$3$
    $P(X)$$(\frac{4}{7})^3$$\frac{12}{7} \times (\frac{4}{7})^2$$\frac{9}{7} \times (\frac{3}{7})^2$$(\frac{3}{7})^3$

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