(A) $\sin 690^{\circ} \times \sec 240^{\circ}$ $= \sin (2 \times 360^{\circ} - 30^{\circ}) \times \sec (180^{\circ} + 60^{\circ})$ $= \sin (-30^{\circ

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(A) $\sin 690^{\circ} \times \sec 240^{\circ}$ $= \sin (2 \times 360^{\circ} - 30^{\circ}) \times \sec (180^{\circ} + 60^{\circ})$ $= \sin (-30^{\circ}) \times (-\sec 60^{\circ})$ $= (-\sin 30^{\circ}) \times (-2)$ $= (-\frac{1}{2}) \times (-2) = 1$

Class 11 Mathematics Trigonometrical Ratios, Functions and Identities Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

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$\sin 690^{\circ} \times \sec 240^{\circ} = $

MHT CET 2020 All MHT CET

A
$1$
B
$-1$
C
$\frac{-1}{2}$
D
$\frac{1}{2}$

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Trigonometrical Ratios, Functions and Identities

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Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

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$\sin 690^{\circ} \times \sec 240^{\circ} = $

Similar Questions

$\cos A + \sin (270^\circ + A) - \sin (270^\circ - A) + \cos (180^\circ + A) = $

If $A = \sin 45^{\circ} + \cos 45^{\circ}$ and $B = \sin 44^{\circ} + \cos 44^{\circ}$,then

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