(A) We know that $\sin \theta + \cos \theta = \sqrt{2} \sin(\theta + 45^{\circ})$.For $A$,$\theta = 45^{\circ}$,so $A = \sqrt{2} \sin(45^{\circ} + 45^

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(A) We know that $\sin \theta + \cos \theta = \sqrt{2} \sin(\theta + 45^{\circ})$.For $A$,$\theta = 45^{\circ}$,so $A = \sqrt{2} \sin(45^{\circ} + 45^{\circ}) = \sqrt{2} \sin 90^{\circ} = \sqrt{2}(1) = \sqrt{2}$.For $B$,$\theta = 44^{\circ}$,so $B = \sqrt{2} \sin(44^{\circ} + 45^{\circ}) = \sqrt{2} \sin 89^{\circ}$.Since $\sin 89^{\circ} Therefore,$B B$.

Class 11 Mathematics Trigonometrical Ratios, Functions and Identities Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

If $A = \sin 45^{\circ} + \cos 45^{\circ}$ and $B = \sin 44^{\circ} + \cos 44^{\circ}$,then

A
$A > B$
B
$A < B$
C
$A = B$
D
none of these

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Trigonometrical Ratios, Functions and Identities

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Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

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EasyMHT CET 2020

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Let $\theta$ be an angle in the standard position such that the point $(-5, 12)$ lies on its terminal side. Then:

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What are the polar coordinates of $(-\sqrt{3}, -1)$?

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If $A = \sin 45^{\circ} + \cos 45^{\circ}$ and $B = \sin 44^{\circ} + \cos 44^{\circ}$,then

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