$A$ capacitor of unknown capacitance $C$ is connected across a battery of $V$ volt. The charge stored in it becomes $Q$ coulomb. When the potential across the capacitor is reduced by $V^{\prime}$ volt,the charge stored in it becomes $Q^{\prime}$ coulomb. The capacitance $C$ is:

  • A
    $\frac{Q-Q^{\prime}}{\sqrt{V^{\prime}}}$
  • B
    $\frac{V^{\prime}}{Q-Q^{\prime}}$
  • C
    $\frac{Q+Q^{\prime}}{V^{\prime}}$
  • D
    $\frac{Q-Q^{\prime}}{V^{\prime}}$

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