Class 12PhysicsMoving Charges and MagnetismThe Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion
Difficult$A$ galvanometer of resistance $20 \Omega$ gives a deflection of $5$ divisions when $1 \text{ mA}$ current flows through it. The galvanometer scale has $50$ divisions. To convert the galvanometer into a voltmeter of range $25 \text{ V}$,we should connect a resistance of
- A$1240 \Omega$ in series.
- B$2480 \Omega$ in series.
- C$2480 \Omega$ in parallel.
- D$20 \Omega$ in parallel.
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Similar Questions
$A$ galvanometer having a resistance $G$ and current $I_g$ flowing in it,produces full-scale deflection. If $S_1$ is the value of the shunt which converts it into an ammeter of range $0-I$ and $S_2$ is the value of the shunt for range $0-8I$,then the ratio $\frac{S_1}{S_2}$ will be:
Medium
View SolutionIf the number of turns in the coil of a galvanometer is decreased,then the resistance of the galvanometer:
This question has Statement-$I$ and Statement-$II$. Of the four choices given after the statements,choose the one that best describes the two statements.
Statement-$I$: Higher the range,greater is the resistance of an ammeter.
Statement-$II$: To increase the range of an ammeter,an additional shunt needs to be used across it.
Statement-$I$: Higher the range,greater is the resistance of an ammeter.
Statement-$II$: To increase the range of an ammeter,an additional shunt needs to be used across it.
$A$ galvanometer of resistance $50 \Omega$ is connected to a battery of $3 \text{ V}$ along with a resistance of $2950 \Omega$ in series. $A$ full-scale deflection of $30$ divisions is obtained in the galvanometer. In order to reduce this deflection to $20$ divisions,the resistance in series should be: (in $\Omega$)
DifficultKCET 2022
View Solution$A$ galvanometer may be converted into an ammeter or a voltmeter. In which of the following cases will the resistance of the device be the largest? (Assume the maximum range of the galvanometer is $1 \, mA$)
Medium
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