$A$ bar magnet has length $3 \,cm$, cross-sectional area $2 \,cm^2$ and magnetic moment $3 \,Am^2$. The intensity of magnetization of the bar magnet is

  • A
    $2 \times 10^5 \,A/m$
  • B
    $3 \times 10^5 \,A/m$
  • C
    $4 \times 10^5 \,A/m$
  • D
    $5 \times 10^5 \,A/m$

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If $M$ is the magnetisation induced in the material,$H$ is the magnetic field intensity,and $B$ is the net magnetic field inside the material,then the correct relation between them is $(\mu_0 = \text{permeability of free space})$

An iron rod of susceptibility $599$ is subjected to a magnetising field of $1200 \, A m^{-1}$. The permeability of the material of the rod is $(\mu_{0} = 4 \pi \times 10^{-7} \, T m A^{-1})$.

$A$ substance has a mass of $1 \, g$ and a density of $5 \, g/cm^3$. Its magnetic dipole moment is $6 \times 10^{-7} \, A \cdot m^2$. What is the magnetization in $A/m$?

$A$ solenoid has a core of a material with relative permeability $400$. The windings of the solenoid are insulated from the core and carry a current of $2 \; A$. If the number of turns is $1000$ per metre,calculate $(a) \; H$,$(b) \; M$,$(c) \; B$ and $(d)$ the magnetising current $I_m$.

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