$A$ lead bullet moving with velocity $V$ strikes a wall and stops. If $75 \%$ of its energy is converted into heat,then the increase in temperature is ($s=$ specific heat of lead,$J=$ mechanical equivalent of heat).

  • A
    $\frac{3 V^2}{8 Js}$
  • B
    $\frac{5 V^2}{8 Js}$
  • C
    $\frac{3 V^2}{4 Js}$
  • D
    $\frac{5 V^2}{4 Js}$

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