$\frac{\cos 10^o + \sin 10^o}{\cos 10^o - \sin 10^o} = $

  • A
    $\tan 55^o$
  • B
    $\cot 55^o$
  • C
    $-\tan 35^o$
  • D
    $-\cot 35^o$

Explore More

Similar Questions

કિંમત શોધો: $\sin (\beta + \gamma - \alpha ) + \sin (\gamma + \alpha - \beta ) + \sin (\alpha + \beta - \gamma ) - \sin (\alpha + \beta + \gamma )$

$1+\cos 10^{\circ}+\cos 20^{\circ}+\cos 30^{\circ}=$

ધારો કે $\cos (\alpha+\beta)=\frac{4}{5}$ અને $\sin (\alpha-\beta)=\frac{5}{13}$,જ્યાં $0 \leq \alpha, \beta \leq \frac{\pi}{4}$,તો $\tan 2 \alpha=$

જો $\sin x + \sin y = \frac{1}{2}$ અને $\cos x + \cos y = 1$ હોય,તો $\tan(x + y) = $

ધારો કે $\theta_1$ અને $\theta_2$ એવા છે કે જેથી $(\theta_1-\theta_2)$ એ $3^{\text{rd}}$ અથવા $4^{\text{th}}$ ચરણમાં આવે છે. જો $\sin \theta_1+\sin \theta_2=-\frac{21}{65}$ અને $\cos \theta_1+\cos \theta_2=-\frac{27}{65}$ હોય,તો $\cos \left(\frac{\theta_1-\theta_2}{2}\right)=$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo