cos 2(theta + phi) - 4cos (theta + phi)sin th | vedclass

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(A) दिया गया व्यंजक: $E = \cos 2(	heta + \phi) - 4\cos (	heta + \phi)\sin 	heta \sin \phi + 2\sin^2 \phi$$	heta = \frac{\pi}{4}$ और $\phi = \frac{

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$\cos 2	heta$

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(A) दिया गया व्यंजक: $E = \cos 2(	heta + \phi) - 4\cos (	heta + \phi)\sin 	heta \sin \phi + 2\sin^2 \phi$$	heta = \frac{\pi}{4}$ और $\phi = \frac{\pi}{4}$ रखने पर:$E = \cos 2(\frac{\pi}{2}) - 4\cos(\frac{\pi}{2})\sin(\frac{\pi}{4})\sin(\frac{\pi}{4}) + 2\sin^2(\frac{\pi}{4})$$E = -1 - 0 + 1 = 0$.विकल्प $(a)$ में मान रखने पर: $\cos 2(\frac{\pi}{4}) = \cos(\frac{\pi}{2}) = 0$.अतः,विकल्प $(a)$ सही है।

$\cos 2(\theta + \phi) - 4\cos (\theta + \phi)\sin \theta \sin \phi + 2\sin^2 \phi = $

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