A radio receiver antenna that is 4 , m long i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given that, length of antenna, $l = 4 \, m$.Intensity of signal, $I = 8 	imes 10^{-16} \, W/m^2$.The intensity of an electromagnetic wave is give

Vedclass · Accepted Answer

$3.1$

Vedclass · Answer

(B) Given that, length of antenna, $l = 4 \, m$.Intensity of signal, $I = 8 	imes 10^{-16} \, W/m^2$.The intensity of an electromagnetic wave is given by $I = \frac{1}{2} \varepsilon_0 c E_0^2$, where $E_0$ is the maximum electric field amplitude.Rearranging for $E_0$, we get $E_0 = \sqrt{\frac{2I}{\varepsilon_0 c}}$.Substituting the values ($\varepsilon_0 = 8.85 	imes 10^{-12} \, F/m$, $c = 3 	imes 10^8 \, m/s$):$E_0 = \sqrt{\frac{2 	imes 8 	imes 10^{-16}}{8.85 	imes 10^{-12} 	imes 3 	imes 10^8}} = \sqrt{\frac{16 	imes 10^{-16}}{26.55 	imes 10^{-4}}} = \sqrt{0.6026 	imes 10^{-12}} \approx 0.776 	imes 10^{-6} \, V/m$.The maximum potential difference $V_0$ across the antenna is $V_0 = E_0 	imes l$.$V_0 = 0.776 	imes 10^{-6} \, V/m 	imes 4 \, m = 3.104 	imes 10^{-6} \, V \approx 3.1 \, \mu V$.

$A$ radio receiver antenna that is $4 \, m$ long is oriented along the direction of the electromagnetic wave and it receives a signal of intensity $8 \times 10^{-16} \, W/m^2$. The maximum instantaneous potential difference across the two ends of the antenna is (in $ \, \mu V$)

Similar Questions

The efficiency of a bulb of power $60 \ W$ is $16 \%$. The peak value of the electric field produced by the electromagnetic radiation from the bulb at a distance of $2 \ m$ from the bulb is $\left(\frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \ Nm^2 C^{-2}\right)$ (in $Vm^{-1}$)

Electromagnetic theory suggests that light consists of

If a source is transmitting electromagnetic waves of frequency $8.2 \times 10^6 \,Hz$, then the wavelength of the electromagnetic waves transmitted from the source will be (in $\,m$)

In an electromagnetic wave,the electric field $\vec{E}$ and the magnetic field $\vec{B}$ oscillate in the region near the source as:

The electric field of a plane electromagnetic wave is given by: $E_y = 69 \sin[0.6 \times 10^3 x - 1.8 \times 10^{11} t] \text{ V/m}$. The expression for the magnetic field associated with this electromagnetic wave is . . . . . . $T$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module