A galvanometer of resistance 10 Omega changes | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The galvanometer resistance is $G = 10 \Omega$. The full-scale deflection current is $I_g = 1 	ext{ mA} = 1 	imes 10^{-3} 	ext{ A}$. The new ra

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(A) The galvanometer resistance is $G = 10 \Omega$. The full-scale deflection current is $I_g = 1 	ext{ mA} = 1 	imes 10^{-3} 	ext{ A}$. The new range is $I = 101 	ext{ mA} = 101 	imes 10^{-3} 	ext{ A}$.To convert a galvanometer into an ammeter,a shunt resistance $S$ is connected in parallel.The formula for shunt resistance is $S = \frac{I_g G}{I - I_g}$.Substituting the values: $S = \frac{1 	imes 10^{-3} 	imes 10}{101 	imes 10^{-3} - 1 	imes 10^{-3}} = \frac{10 	imes 10^{-3}}{100 	imes 10^{-3}} = 0.1 \Omega$.The resistance of a wire is given by $R = ho \frac{L}{A}$,where $ho = 1 	imes 10^{-6} \Omega 	ext{ m}$ and $A = 1 	ext{ mm}^2 = 1 	imes 10^{-6} 	ext{ m}^2$.Setting $R = S = 0.1 \Omega$,we get $0.1 = (1 	imes 10^{-6}) 	imes \frac{L}{1 	imes 10^{-6}}$.$0.1 = L$.Thus,$L = 0.1 	ext{ m} = 10 	ext{ cm}$.

Similar Questions

$A$ galvanometer of $25 \,\Omega$ resistance can read a maximum current of $6 \,mA$. It can be used as a voltmeter to measure a maximum of $6 \,V$ by connecting a resistance to the galvanometer. Identify the correct choice in the given answers.

When a moving coil galvanometer $(MCG)$ is converted into a voltmeter,the series resistance is '$n$' times the resistance of the galvanometer. How many times the original voltage range of the $MCG$ is the voltmeter now capable of measuring?

$A$ galvanometer has a coil of resistance $200 \Omega$ with a full scale deflection at $20 \mu A$. The value of resistance to be added to use it as an ammeter of range $(0-20) mA$ is: (in $\Omega$)

$A$ galvanometer has resistance $G$ and range $V_g$. How much resistance is required to read voltage up to $V$ volt?

$A$ galvanometer of $50 \, \Omega$ resistance has $25$ divisions. $A$ current of $4 \times 10^{-4} \, A$ gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of $25 \, V$, it should be connected with a resistance of

Vedclass Test Series

Exam Paper Generator

Online Exam Module