A galvanometer of 25 ,Omega resistance can re | vedclass

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(C) To convert a galvanometer into a voltmeter,a high resistance $R$ must be connected in series with the galvanometer.Given: Galvanometer resistance

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$975 \,\Omega$ in series

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(C) To convert a galvanometer into a voltmeter,a high resistance $R$ must be connected in series with the galvanometer.Given: Galvanometer resistance $G = 25 \,\Omega$,full-scale deflection current $i_g = 6 \,mA = 6 	imes 10^{-3} \,A$,and maximum voltage to be measured $V = 6 \,V$.The formula for the series resistance $R$ is given by $R = \frac{V}{i_g} - G$.Substituting the values: $R = \frac{6}{6 	imes 10^{-3}} - 25$.$R = 1000 - 25 = 975 \,\Omega$.Thus,a resistance of $975 \,\Omega$ must be connected in series.

$A$ galvanometer of $25 \,\Omega$ resistance can read a maximum current of $6 \,mA$. It can be used as a voltmeter to measure a maximum of $6 \,V$ by connecting a resistance to the galvanometer. Identify the correct choice in the given answers.

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