$A$ uniform rod of length $l$ and density $\rho$ is revolving about a vertical axis passing through its one end. If $\omega$ is the angular velocity of the rod,then the centrifugal force per unit area of the rod is

  • A
    $\frac{\rho \omega^2 l^2}{4}$
  • B
    $\frac{\rho \omega^2 l^2}{12}$
  • C
    $\frac{\rho \omega^2 l^2}{2}$
  • D
    $\frac{\rho \omega^2 l^2}{8}$

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