Difficult
$\left[\begin{array}{ccc} 1 & 2 & 3 \\ -1 & 1 & 2 \\ 3 & 0 & 2 \end{array}\right]^{\left|\begin{array}{cc} 2022 & 2024 \\ 2021 & 2023 \end{array}\right|}$ ની કિંમત શોધો.
- A$\left[\begin{array}{ccc} 8 & 4 & 11 \\ 4 & -1 & 3 \\ 9 & 6 & 13 \end{array}\right]$
- B$\left[\begin{array}{ccc} 8 & 4 & 13 \\ 4 & -1 & 3 \\ 9 & 6 & 12 \end{array}\right]$
- C$\left[\begin{array}{ccc} 8 & 4 & 13 \\ 4 & -1 & 3 \\ 9 & 6 & 13 \end{array}\right]$
- D$\left[\begin{array}{ccc} 8 & 4 & 11 \\ 4 & 1 & 13 \\ 9 & 6 & 13 \end{array}\right]$
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વિધાનો પૈકી:
$I$: જો $\begin{vmatrix} 1 & \cos \alpha & \cos \beta \\ \cos \alpha & 1 & \cos \gamma \\ \cos \beta & \cos \gamma & 1 \end{vmatrix} = \begin{vmatrix} 0 & \cos \alpha & \cos \beta \\ \cos \alpha & 0 & \cos \gamma \\ \cos \beta & \cos \gamma & 0 \end{vmatrix}$ હોય, તો $\cos^{2}\alpha+\cos^{2}\beta+\cos^{2}\gamma=\frac{3}{2}$
$II$: જો $\begin{vmatrix} x^{2}+x & x+1 & x-2 \\ 2x^{2}+3x-1 & 3x & 3x-3 \\ x^{2}+2x+3 & 2x-1 & 2x-1 \end{vmatrix} = px+q$ હોય, તો $p^{2}=196q^{2}$
$I$: જો $\begin{vmatrix} 1 & \cos \alpha & \cos \beta \\ \cos \alpha & 1 & \cos \gamma \\ \cos \beta & \cos \gamma & 1 \end{vmatrix} = \begin{vmatrix} 0 & \cos \alpha & \cos \beta \\ \cos \alpha & 0 & \cos \gamma \\ \cos \beta & \cos \gamma & 0 \end{vmatrix}$ હોય, તો $\cos^{2}\alpha+\cos^{2}\beta+\cos^{2}\gamma=\frac{3}{2}$
$II$: જો $\begin{vmatrix} x^{2}+x & x+1 & x-2 \\ 2x^{2}+3x-1 & 3x & 3x-3 \\ x^{2}+2x+3 & 2x-1 & 2x-1 \end{vmatrix} = px+q$ હોય, તો $p^{2}=196q^{2}$
DifficultJEE MAIN 2026
View Solution$A = \frac{1}{\pi} \begin{bmatrix} \sin^{-1}(\pi x) & \tan^{-1}(\frac{x}{\pi}) \\ \sin^{-1}(\frac{x}{\pi}) & \cot^{-1}(\pi x) \end{bmatrix}$ અને $B = \frac{1}{\pi} \begin{bmatrix} -\cos^{-1}(\pi x) & \tan^{-1}(\frac{x}{\pi}) \\ \sin^{-1}(\frac{x}{\pi}) & -\tan^{-1}(\pi x) \end{bmatrix}$ હોય,તો $A - B = $ . . . . . . .
જો $\frac{x^2+7}{(x^2+1)(x-2)}=\frac{A}{x-2}+\frac{Bx+C}{x^2+1}$ હોય, તો શ્રેણિક $\begin{bmatrix} A & B \\ C & \frac{2}{5} \end{bmatrix}$ નો નિશ્ચાયક શોધો.
ધારો કે $A$ એક એવો શ્રેણિક છે કે જેથી $A \cdot \begin{bmatrix} 1 & 2 \\ 0 & 3 \end{bmatrix}$ એક અદિશ શ્રેણિક (scalar matrix) છે અને $|3A| = 108$ છે. તો $A^2$ બરાબર શું થાય?
DifficultJEE MAIN 2018
View Solutionજો શ્રેણિક $A = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 3 & 0 & -1 \end{bmatrix}$ એ સમીકરણ $A^{20} + \alpha A^{19} + \beta A = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 4 & 0 \\ 0 & 0 & 1 \end{bmatrix}$ નું સમાધાન કરે છે,જ્યાં $\alpha$ અને $\beta$ વાસ્તવિક સંખ્યાઓ છે,તો $\beta - \alpha$ ની કિંમત ........ થાય.
DifficultJEE MAIN 2021
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