$\int \frac{1+\cos 4 x}{\cot x-\tan x} d x$ is equal to

  • A
    $-\frac{1}{4} \cos 4 x+C$
  • B
    $\frac{1}{8} \cos 4 x+C$
  • C
    $\frac{1}{4} \sin 4 x+C$
  • D
    $-\frac{1}{8} \cos 4 x+C$

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