$\lim _{x \rightarrow 0} \frac{3^{\sin x}-2^{\tan x}}{\sin x}=$

  • A
    $0$
  • B
    $1$
  • C
    $\log _e 6$
  • D
    $\log _e \frac{3}{2}$

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જો $f(x) = \begin{cases} \frac{\sin(1+[x])}{[x]}, & \text{for } [x] \neq 0 \\ 0, & \text{for } [x] = 0 \end{cases}$ જ્યાં $[x]$ એ મહત્તમ પૂર્ણાંક વિધેય દર્શાવે છે,તો $\lim_{x \rightarrow 0^{-}} f(x)$ ની કિંમત શોધો.

$\lim _{x}$ ${\rightarrow 0^{+}} \frac{\tan \left(5(x)^{\frac{1}{3}}\right) \log _e\left(1+3 x^2\right)}{\left(\tan ^{-1} 3 \sqrt{x}\right)^2\left(e^{5(x)^{\frac{4}{3}}}-1\right)}$ ની કિંમત શોધો.

$\mathop {{\rm{lim}}}\limits_{x \to 0} \frac{{\left( {1 - \cos 2x} \right)\left( {3 + \cos x} \right)}}{{x\tan 4x}} = $

જો $\lim _{n \rightarrow \infty} x_n$ અસ્તિત્વ ધરાવે છે અને તે શાંત છે,$x_1=2$,$x_{n+1}=\frac{a+b x_n}{b+c x_n}$ દરેક $n \in N$ માટે,અને $c > b > a > 0$ હોય,તો $\lim _{n \rightarrow \infty} x_n =$

$\lim _{x \rightarrow 0} \left( \frac{1}{x} \ln \sqrt{\frac{1+x}{1-x}} \right)$ ની કિંમત શોધો.

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